Hi, here in Chapter 5.2 I read that the dbg! macro takes ownership instead of taking reference

https://github.com/rust-lang/book/blob/f78ab89d7545ac17780e6a367055cc089f4cd2ec/src/ch05-02-example-structs.md?plain=1#L196C1-L198C40

and its use is dbg!(&rect1).

However, this seems in contrast with what I read in Chapter 4.2, that for example the function calculate_length takes a reference instead of taking ownership (calculate_length(&s1)).

https://github.com/rust-lang/book/blob/f78ab89d7545ac17780e6a367055cc089f4cd2ec/src/ch04-02-references-and-borrowing.md?plain=1#L12C40-L13C79

Am I misunderstanding how dbg! works or it is also taking a reference (and println! takes ownership instead)?