How to produce an output similar to bison/byacc for debugging ? #51
Description
The error messages from lalr for shift/reduce and reduce/reduce conflicts are a bit dry.
How to produce an output similar to the ones bison/byacc produce when specifying -v ?
byacc:
...
state 8
lines : lines line * (2)
. reduce 2
9: shift/reduce conflict (shift 20, reduce 16 [vexp]) on '+'
9: shift/reduce conflict (shift 21, reduce 16 [vexp]) on '-'
9: shift/reduce conflict (shift 22, reduce 16 [vexp]) on '*'
9: shift/reduce conflict (shift 23, reduce 16 [vexp]) on '/'
9: shift/reduce conflict (shift 24, reduce 16 [vexp]) on '\n'
state 9
line : dexp * '\n' (3)
dexp : dexp * '+' dexp (10)
dexp : dexp * '-' dexp (11)
dexp : dexp * '*' dexp (12)
dexp : dexp * '/' dexp (13)
vexp : dexp * (16)
vexp : dexp * '+' vexp (20)
vexp : dexp * '-' vexp (22)
vexp : dexp * '*' vexp (24)
vexp : dexp * '/' vexp (26)
'+' shift 20
'-' shift 21
'*' shift 22
'/' shift 23
'\n' shift 24
state 10
...
bison:
...
State 9
2 lines: lines line •
$default reduce using rule 2 (lines)
State 10
3 line: dexp • '\n'
10 dexp: dexp • '+' dexp
11 | dexp • '-' dexp
12 | dexp • '*' dexp
13 | dexp • '/' dexp
16 vexp: dexp •
20 | dexp • '+' vexp
22 | dexp • '-' vexp
24 | dexp • '*' vexp
26 | dexp • '/' vexp
'+' shift, and go to state 21
'-' shift, and go to state 22
'*' shift, and go to state 23
'/' shift, and go to state 24
'\n' shift, and go to state 25
'+' [reduce using rule 16 (vexp)]
'-' [reduce using rule 16 (vexp)]
'*' [reduce using rule 16 (vexp)]
'/' [reduce using rule 16 (vexp)]
'\n' [reduce using rule 16 (vexp)]
State 11
...