defmodule Keyword do
  @moduledoc """
  A set of functions for working with keywords.

  A keyword is a list of two-element tuples where the first
  element of the tuple is an atom and the second element
  can be any value.

  A keyword may have duplicated keys so it is not strictly
  a key-value store. However most of the functions in this module
  behave exactly as a dictionary so they work similarly to
  the functions you would find in the `Map` module.

  For example, `Keyword.get/3` will get the first entry matching
  the given key, regardless if duplicated entries exist.
  Similarly, `Keyword.put/3` and `Keyword.delete/3` ensure all
  duplicated entries for a given key are removed when invoked.

  A handful of functions exist to handle duplicated keys, in
  particular, `Enum.into/2` allows creating new keywords without
  removing duplicated keys, `get_values/2` returns all values for
  a given key and `delete_first/2` deletes just one of the existing
  entries.

  The functions in Keyword do not guarantee any property when
  it comes to ordering. However, since a keyword list is simply a
  list, all the operations defined in `Enum` and `List` can be
  applied too, especially when ordering is required.
  """

  @compile :inline_list_funcs

  @type key :: atom
  @type value :: any

  @type t :: [{key, value}]
  @type t(value) :: [{key, value}]

  @doc """
  Returns `true` if `term` is a keyword list; otherwise returns `false`.

  ## Examples

      iex> Keyword.keyword?([])
      true
      iex> Keyword.keyword?([a: 1])
      true
      iex> Keyword.keyword?([{Foo, 1}])
      true
      iex> Keyword.keyword?([{}])
      false
      iex> Keyword.keyword?([:key])
      false
      iex> Keyword.keyword?(%{})
      false

  """
  @spec keyword?(term) :: boolean
  def keyword?(term)

  def keyword?([{key, _value} | rest]) when is_atom(key), do: keyword?(rest)
  def keyword?([]),     do: true
  def keyword?(_other), do: false

  @doc """
  Returns an empty keyword list, i.e. an empty list.

  ## Examples

      iex> Keyword.new()
      []

  """
  @spec new :: []
  def new, do: []

  @doc """
  Creates a keyword from an enumerable.

  Duplicated entries are removed, the latest one prevails.
  Unlike `Enum.into(enumerable, [])`, `Keyword.new(enumerable)`
  guarantees the keys are unique.

  ## Examples

      iex> Keyword.new([{:b, 1}, {:a, 2}])
      [b: 1, a: 2]

      iex> Keyword.new([{:a, 1}, {:a, 2}, {:a, 3}])
      [a: 3]

  """
  @spec new(Enum.t) :: t
  def new(pairs) do
    new(pairs, fn pair -> pair end)
  end

  @doc """
  Creates a keyword from an enumerable via the transformation function.

  Duplicated entries are removed, the latest one prevails.
  Unlike `Enum.into(enumerable, [], fun)`,
  `Keyword.new(enumerable, fun)` guarantees the keys are unique.

  ## Examples

      iex> Keyword.new([:a, :b], fn(x) -> {x, x} end)
      [a: :a, b: :b]

  """
  @spec new(Enum.t, (term -> {key, value})) :: t
  def new(pairs, transform) do
    fun = fn el, acc ->
      {k, v} = transform.(el)
      put_new(acc, k, v)
    end
    :lists.foldl(fun, [], Enum.reverse(pairs))
  end

  @doc """
  Gets the value for a specific `key`.

  If `key` does not exist, return the default value
  (`nil` if no default value).

  If duplicated entries exist, the first one is returned.
  Use `get_values/2` to retrieve all entries.

  ## Examples

      iex> Keyword.get([], :a)
      nil
      iex> Keyword.get([a: 1], :a)
      1
      iex> Keyword.get([a: 1], :b)
      nil
      iex> Keyword.get([a: 1], :b, 3)
      3

  With duplicated keys:

      iex> Keyword.get([a: 1, a: 2], :a, 3)
      1
      iex> Keyword.get([a: 1, a: 2], :b, 3)
      3

  """
  @spec get(t, key) :: value
  @spec get(t, key, value) :: value
  def get(keywords, key, default \\ nil) when is_list(keywords) and is_atom(key) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, value} -> value
      false -> default
    end
  end

  @doc """
  Gets the value for a specific `key`.

  If `key` does not exist, lazily evaluates `fun` and returns its result.

  This is useful if the default value is very expensive to calculate or
  generally difficult to setup and teardown again.

  If duplicated entries exist, the first one is returned.
  Use `get_values/2` to retrieve all entries.

  ## Examples

      iex> keyword = [a: 1]
      iex> fun = fn ->
      ...>   # some expensive operation here
      ...>   13
      ...> end
      iex> Keyword.get_lazy(keyword, :a, fun)
      1
      iex> Keyword.get_lazy(keyword, :b, fun)
      13

  """
  @spec get_lazy(t, key, (() -> value)) :: value
  def get_lazy(keywords, key, fun)
      when is_list(keywords) and is_atom(key) and is_function(fun, 0) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, value} -> value
      false -> fun.()
    end
  end

  @doc """
  Gets the value from `key` and updates it, all in one pass.

  This `fun` argument receives the value of `key` (or `nil` if `key`
  is not present) and must return a two-element tuple: the "get" value
  (the retrieved value, which can be operated on before being returned)
  and the new value to be stored under `key`. The `fun` may also
  return `:pop`, implying the current value shall be removed from the
  keyword list and returned.

  The returned value is a tuple with the "get" value returned by
  `fun` and a new keyword list with the updated value under `key`.

  ## Examples

      iex> Keyword.get_and_update([a: 1], :a, fn current_value ->
      ...>   {current_value, "new value!"}
      ...> end)
      {1, [a: "new value!"]}

      iex> Keyword.get_and_update([a: 1], :b, fn current_value ->
      ...>   {current_value, "new value!"}
      ...> end)
      {nil, [b: "new value!", a: 1]}

      iex> Keyword.get_and_update([a: 1], :a, fn _ -> :pop end)
      {1, []}

      iex> Keyword.get_and_update([a: 1], :b, fn _ -> :pop end)
      {nil, [a: 1]}

  """
  @spec get_and_update(t, key, (value -> {get, value} | :pop)) :: {get, t} when get: term
  def get_and_update(keywords, key, fun)
    when is_list(keywords) and is_atom(key),
    do: get_and_update(keywords, [], key, fun)

  defp get_and_update([{key, current} | t], acc, key, fun) do
    case fun.(current) do
      {get, value} ->
        {get, :lists.reverse(acc, [{key, value} | t])}
      :pop ->
        {current, :lists.reverse(acc, t)}
      other ->
        raise "the given function must return a two-element tuple or :pop, got: #{inspect(other)}"
    end
  end

  defp get_and_update([{_, _} = h | t], acc, key, fun),
    do: get_and_update(t, [h | acc], key, fun)

  defp get_and_update([], acc, key, fun) do
    case fun.(nil) do
      {get, update} ->
        {get, [{key, update} | :lists.reverse(acc)]}
      :pop ->
        {nil, :lists.reverse(acc)}
      other ->
        raise "the given function must return a two-element tuple or :pop, got: #{inspect(other)}"
    end
  end

  @doc """
  Gets the value from `key` and updates it. Raises if there is no `key`.

  This `fun` argument receives the value of `key` and must return a
  two-element tuple: the "get" value (the retrieved value, which can be
  operated on before being returned) and the new value to be stored under
  `key`.

  The returned value is a tuple with the "get" value returned by `fun` and a new
  keyword list with the updated value under `key`.

  ## Examples

      iex> Keyword.get_and_update!([a: 1], :a, fn current_value ->
      ...>   {current_value, "new value!"}
      ...> end)
      {1, [a: "new value!"]}

      iex> Keyword.get_and_update!([a: 1], :b, fn current_value ->
      ...>   {current_value, "new value!"}
      ...> end)
      ** (KeyError) key :b not found in: [a: 1]

      iex> Keyword.get_and_update!([a: 1], :a, fn _ ->
      ...>   :pop
      ...> end)
      {1, []}

  """
  @spec get_and_update!(t, key, (value -> {get, value})) :: {get, t} | no_return when get: term
  def get_and_update!(keywords, key, fun) do
    get_and_update!(keywords, key, fun, [])
  end

  defp get_and_update!([{key, value} | keywords], key, fun, acc) do
    case fun.(value) do
      {get, value} ->
        {get, :lists.reverse(acc, [{key, value} | delete(keywords, key)])}
      :pop ->
        {value, :lists.reverse(acc, keywords)}
      other ->
        raise "the given function must return a two-element tuple or :pop, got: #{inspect(other)}"
    end
  end

  defp get_and_update!([{_, _} = e | keywords], key, fun, acc) do
    get_and_update!(keywords, key, fun, [e | acc])
  end

  defp get_and_update!([], key, _fun, acc) when is_atom(key) do
    raise(KeyError, key: key, term: acc)
  end

  @doc """
  Fetches the value for a specific `key` and returns it in a tuple.

  If the `key` does not exist, returns `:error`.

  ## Examples

      iex> Keyword.fetch([a: 1], :a)
      {:ok, 1}
      iex> Keyword.fetch([a: 1], :b)
      :error

  """
  @spec fetch(t, key) :: {:ok, value} | :error
  def fetch(keywords, key) when is_list(keywords) and is_atom(key) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, value} -> {:ok, value}
      false -> :error
    end
  end

  @doc """
  Fetches the value for specific `key`.

  If `key` does not exist, a `KeyError` is raised.

  ## Examples

      iex> Keyword.fetch!([a: 1], :a)
      1
      iex> Keyword.fetch!([a: 1], :b)
      ** (KeyError) key :b not found in: [a: 1]

  """
  @spec fetch!(t, key) :: value | no_return
  def fetch!(keywords, key) when is_list(keywords) and is_atom(key) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, value} -> value
      false -> raise(KeyError, key: key, term: keywords)
    end
  end

  @doc """
  Gets all values for a specific `key`.

  ## Examples

      iex> Keyword.get_values([], :a)
      []
      iex> Keyword.get_values([a: 1], :a)
      [1]
      iex> Keyword.get_values([a: 1, a: 2], :a)
      [1, 2]

  """
  @spec get_values(t, key) :: [value]
  def get_values(keywords, key) when is_list(keywords) and is_atom(key) do
    fun = fn
      {^key, val} -> {true, val}
      {_, _} -> false
    end
    :lists.filtermap(fun, keywords)
  end

  @doc """
  Returns all keys from the keyword list.

  Duplicated keys appear duplicated in the final list of keys.

  ## Examples

      iex> Keyword.keys([a: 1, b: 2])
      [:a, :b]
      iex> Keyword.keys([a: 1, b: 2, a: 3])
      [:a, :b, :a]

  """
  @spec keys(t) :: [key]
  def keys(keywords) when is_list(keywords) do
    :lists.map(fn {k, _} -> k end, keywords)
  end

  @doc """
  Returns all values from the keyword list.

  Values from duplicated keys will be kept in the final list of values.

  ## Examples

      iex> Keyword.values([a: 1, b: 2])
      [1, 2]
      iex> Keyword.values([a: 1, b: 2, a: 3])
      [1, 2, 3]

  """
  @spec values(t) :: [value]
  def values(keywords) when is_list(keywords) do
    :lists.map(fn {_, v} -> v end, keywords)
  end

  @doc """
  Deletes the entries in the keyword list for a `key` with `value`.

  If no `key` with `value` exists, returns the keyword list unchanged.

  ## Examples

      iex> Keyword.delete([a: 1, b: 2], :a, 1)
      [b: 2]
      iex> Keyword.delete([a: 1, b: 2, a: 3], :a, 3)
      [a: 1, b: 2]
      iex> Keyword.delete([a: 1], :a, 5)
      [a: 1]
      iex> Keyword.delete([a: 1], :b, 5)
      [a: 1]

  """
  @spec delete(t, key, value) :: t
  def delete(keywords, key, value) when is_list(keywords) and is_atom(key) do
    :lists.filter(fn {k, v} -> k != key or v != value end, keywords)
  end

  @doc """
  Deletes the entries in the keyword list for a specific `key`.

  If the `key` does not exist, returns the keyword list unchanged.
  Use `delete_first/2` to delete just the first entry in case of
  duplicated keys.

  ## Examples

      iex> Keyword.delete([a: 1, b: 2], :a)
      [b: 2]
      iex> Keyword.delete([a: 1, b: 2, a: 3], :a)
      [b: 2]
      iex> Keyword.delete([b: 2], :a)
      [b: 2]

  """
  @spec delete(t, key) :: t
  def delete(keywords, key) when is_list(keywords) and is_atom(key) do
    :lists.filter(fn {k, _} -> k != key end, keywords)
  end

  @doc """
  Deletes the first entry in the keyword list for a specific `key`.

  If the `key` does not exist, returns the keyword list unchanged.

  ## Examples

      iex> Keyword.delete_first([a: 1, b: 2, a: 3], :a)
      [b: 2, a: 3]
      iex> Keyword.delete_first([b: 2], :a)
      [b: 2]

  """
  @spec delete_first(t, key) :: t
  def delete_first(keywords, key) when is_list(keywords) and is_atom(key) do
    :lists.keydelete(key, 1, keywords)
  end

  @doc """
  Puts the given `value` under `key`.

  If a previous value is already stored, all entries are
  removed and the value is overridden.

  ## Examples

      iex> Keyword.put([a: 1], :b, 2)
      [b: 2, a: 1]
      iex> Keyword.put([a: 1, b: 2], :a, 3)
      [a: 3, b: 2]
      iex> Keyword.put([a: 1, b: 2, a: 4], :a, 3)
      [a: 3, b: 2]

  """
  @spec put(t, key, value) :: t
  def put(keywords, key, value) when is_list(keywords) and is_atom(key) do
    [{key, value} | delete(keywords, key)]
  end

  @doc """
  Evaluates `fun` and puts the result under `key`
  in keyword list unless `key` is already present.

  This is useful if the value is very expensive to calculate or
  generally difficult to setup and teardown again.

  ## Examples

      iex> keyword = [a: 1]
      iex> fun = fn ->
      ...>   # some expensive operation here
      ...>   3
      ...> end
      iex> Keyword.put_new_lazy(keyword, :a, fun)
      [a: 1]
      iex> Keyword.put_new_lazy(keyword, :b, fun)
      [b: 3, a: 1]

  """
  @spec put_new_lazy(t, key, (() -> value)) :: t
  def put_new_lazy(keywords, key, fun)
      when is_list(keywords) and is_atom(key) and is_function(fun, 0) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, _} -> keywords
      false -> [{key, fun.()} | keywords]
    end
  end

  @doc """
  Puts the given `value` under `key` unless the entry `key`
  already exists.

  ## Examples

      iex> Keyword.put_new([a: 1], :b, 2)
      [b: 2, a: 1]
      iex> Keyword.put_new([a: 1, b: 2], :a, 3)
      [a: 1, b: 2]

  """
  @spec put_new(t, key, value) :: t
  def put_new(keywords, key, value) when is_list(keywords) and is_atom(key) do
    case :lists.keyfind(key, 1, keywords) do
      {^key, _} -> keywords
      false -> [{key, value} | keywords]
    end
  end

  @doc """
  Checks if two keywords are equal.

  Two keywords are considered to be equal if they contain
  the same keys and those keys contain the same values.

  ## Examples

      iex> Keyword.equal?([a: 1, b: 2], [b: 2, a: 1])
      true
      iex> Keyword.equal?([a: 1, b: 2], [b: 1, a: 2])
      false
      iex> Keyword.equal?([a: 1, b: 2, a: 3], [b: 2, a: 3, a: 1])
      true

  """
  @spec equal?(t, t) :: boolean
  def equal?(left, right) when is_list(left) and is_list(right) do
    :lists.sort(left) == :lists.sort(right)
  end

  @doc """
  Merges two keyword lists into one.

  All keys, including duplicated keys, given in `keywords2` will be added
  to `keywords1`, overriding any existing one.

  There are no guarantees about the order of keys in the returned keyword.

  ## Examples

      iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4])
      [b: 2, a: 3, d: 4]

      iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4, a: 5])
      [b: 2, a: 3, d: 4, a: 5]

      iex> Keyword.merge([a: 1], [2, 3])
      ** (ArgumentError) expected a keyword list as the second argument, got: [2, 3]

  """
  @spec merge(t, t) :: t
  def merge(keywords1, keywords2) when is_list(keywords1) and is_list(keywords2) do
    if keyword?(keywords2) do
      fun = fn
        {key, _value} when is_atom(key) ->
          not has_key?(keywords2, key)
        _ ->
          raise ArgumentError, message: "expected a keyword list as the first argument, got: #{inspect keywords1}"
      end
      :lists.filter(fun, keywords1) ++ keywords2
    else
      raise ArgumentError, message: "expected a keyword list as the second argument, got: #{inspect keywords2}"
    end
  end

  @doc """
  Merges two keyword lists into one.

  All keys, including duplicated keys, given in `keywords2` will be added
  to `keywords1`. The given function will be invoked to solve conflicts.

  If `keywords2` has duplicate keys, the given function will be invoked
  for each matching pair in `keywords1`.

  There are no guarantees about the order of keys in the returned keyword.

  ## Examples

      iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4], fn _k, v1, v2 ->
      ...>   v1 + v2
      ...> end)
      [b: 2, a: 4, d: 4]

      iex> Keyword.merge([a: 1, b: 2], [a: 3, d: 4, a: 5], fn :a, v1, v2 ->
      ...>  v1 + v2
      ...> end)
      [b: 2, a: 4, d: 4, a: 5]

      iex> Keyword.merge([a: 1, b: 2, a: 3], [a: 3, d: 4, a: 5], fn :a, v1, v2 ->
      ...>  v1 + v2
      ...> end)
      [b: 2, a: 4, d: 4, a: 8]

      iex> Keyword.merge([a: 1, b: 2], [:a, :b], fn :a, v1, v2 ->
      ...>  v1 + v2
      ...> end)
      ** (ArgumentError) expected a keyword list as the second argument, got: [:a, :b]

  """
  @spec merge(t, t, (key, value, value -> value)) :: t
  def merge(keywords1, keywords2, fun) when is_list(keywords1) and is_list(keywords2) and is_function(fun, 3) do
    if keyword?(keywords1) do
      do_merge(keywords2, [], keywords1, keywords1, fun, keywords2)
    else
      raise ArgumentError, message: "expected a keyword list as the first argument, got: #{inspect keywords1}"
    end
  end

  defp do_merge([{key, value2} | tail], acc, rest, original, fun, keywords2) when is_atom(key) do
    case :lists.keyfind(key, 1, original) do
      {^key, value1} ->
        do_merge(tail, [{key, fun.(key, value1, value2)} | acc],
                 delete(rest, key), :lists.keydelete(key, 1, original), fun, keywords2)

      false ->
        do_merge(tail, [{key, value2} | acc], rest, original, fun, keywords2)
    end
  end

  defp do_merge([], acc, rest, _original, _fun, _keywords2) do
    rest ++ :lists.reverse(acc)
  end

  defp do_merge(_other, _acc, _rest, _original, _fun, keywords2) do
    raise ArgumentError, message: "expected a keyword list as the second argument, got: #{inspect keywords2}"
  end

  @doc """
  Returns whether a given `key` exists in the given `keywords`.

  ## Examples

      iex> Keyword.has_key?([a: 1], :a)
      true
      iex> Keyword.has_key?([a: 1], :b)
      false

  """
  @spec has_key?(t, key) :: boolean
  def has_key?(keywords, key) when is_list(keywords) and is_atom(key) do
    :lists.keymember(key, 1, keywords)
  end

  @doc """
  Updates the `key` with the given function.

  If the `key` does not exist, raises `KeyError`.

  If there are duplicated keys, they are all removed and only the first one
  is updated.

  ## Examples

      iex> Keyword.update!([a: 1], :a, &(&1 * 2))
      [a: 2]
      iex> Keyword.update!([a: 1, a: 2], :a, &(&1 * 2))
      [a: 2]

      iex> Keyword.update!([a: 1], :b, &(&1 * 2))
      ** (KeyError) key :b not found in: [a: 1]

  """
  @spec update!(t, key, (value -> value)) :: t | no_return
  def update!(keywords, key, fun) do
    update!(keywords, key, fun, keywords)
  end

  defp update!([{key, value} | keywords], key, fun, _dict) do
    [{key, fun.(value)} | delete(keywords, key)]
  end

  defp update!([{_, _} = e | keywords], key, fun, dict) do
    [e | update!(keywords, key, fun, dict)]
  end

  defp update!([], key, _fun, dict) when is_atom(key) do
    raise(KeyError, key: key, term: dict)
  end

  @doc """
  Updates the `key` in `keywords` with the given function.

  If the `key` does not exist, inserts the given `initial` value.

  If there are duplicated keys, they are all removed and only the first one
  is updated.

  ## Examples

      iex> Keyword.update([a: 1], :a, 13, &(&1 * 2))
      [a: 2]
      iex> Keyword.update([a: 1, a: 2], :a, 13, &(&1 * 2))
      [a: 2]
      iex> Keyword.update([a: 1], :b, 11, &(&1 * 2))
      [a: 1, b: 11]

  """
  @spec update(t, key, value, (value -> value)) :: t
  def update(keywords, key, initial, fun)

  def update([{key, value} | keywords], key, _initial, fun) do
    [{key, fun.(value)} | delete(keywords, key)]
  end

  def update([{_, _} = e | keywords], key, initial, fun) do
    [e | update(keywords, key, initial, fun)]
  end

  def update([], key, initial, _fun) when is_atom(key) do
    [{key, initial}]
  end

  @doc """
  Takes all entries corresponding to the given keys and extracts them into a
  separate keyword list.

  Returns a tuple with the new list and the old list with removed keys.

  Keys for which there are no entries in the keyword list are ignored.

  Entries with duplicated keys end up in the same keyword list.

  ## Examples

      iex> Keyword.split([a: 1, b: 2, c: 3], [:a, :c, :e])
      {[a: 1, c: 3], [b: 2]}
      iex> Keyword.split([a: 1, b: 2, c: 3, a: 4], [:a, :c, :e])
      {[a: 1, c: 3, a: 4], [b: 2]}

  """
  @spec split(t, [key]) :: {t, t}
  def split(keywords, keys) when is_list(keywords) do
    fun = fn {k, v}, {take, drop} ->
      case k in keys do
        true  -> {[{k, v} | take], drop}
        false -> {take, [{k, v} | drop]}
      end
    end

    acc = {[], []}
    {take, drop} = :lists.foldl(fun, acc, keywords)
    {:lists.reverse(take), :lists.reverse(drop)}
  end

  @doc """
  Takes all entries corresponding to the given keys and returns them in a new
  keyword list.

  Duplicated keys are preserved in the new keyword list.

  ## Examples

      iex> Keyword.take([a: 1, b: 2, c: 3], [:a, :c, :e])
      [a: 1, c: 3]
      iex> Keyword.take([a: 1, b: 2, c: 3, a: 5], [:a, :c, :e])
      [a: 1, c: 3, a: 5]

  """
  @spec take(t, [key]) :: t
  def take(keywords, keys) when is_list(keywords) do
    :lists.filter(fn {k, _} -> k in keys end, keywords)
  end

  @doc """
  Drops the given keys from the keyword list.

  Duplicated keys are preserved in the new keyword list.

  ## Examples

      iex> Keyword.drop([a: 1, b: 2, c: 3], [:b, :d])
      [a: 1, c: 3]
      iex> Keyword.drop([a: 1, b: 2, b: 3, c: 3, a: 5], [:b, :d])
      [a: 1, c: 3, a: 5]

  """
  @spec drop(t, [key]) :: t
  def drop(keywords, keys) when is_list(keywords) do
    :lists.filter(fn {k, _} -> not k in keys end, keywords)
  end

  @doc """
  Returns and removes all values associated with `key` in the keyword list.

  All duplicated keys are removed. See `pop_first/3` for
  removing only the first entry.

  ## Examples

      iex> Keyword.pop([a: 1], :a)
      {1, []}
      iex> Keyword.pop([a: 1], :b)
      {nil, [a: 1]}
      iex> Keyword.pop([a: 1], :b, 3)
      {3, [a: 1]}
      iex> Keyword.pop([a: 1, a: 2], :a)
      {1, []}

  """
  @spec pop(t, key, value) :: {value, t}
  def pop(keywords, key, default \\ nil) when is_list(keywords) do
    case fetch(keywords, key) do
      {:ok, value} ->
        {value, delete(keywords, key)}
      :error ->
        {default, keywords}
    end
  end

  @doc """
  Lazily returns and removes all values associated with `key` in the keyword list.

  This is useful if the default value is very expensive to calculate or
  generally difficult to setup and teardown again.

  All duplicated keys are removed. See `pop_first/3` for
  removing only the first entry.

  ## Examples

      iex> keyword = [a: 1]
      iex> fun = fn ->
      ...>   # some expensive operation here
      ...>   13
      ...> end
      iex> Keyword.pop_lazy(keyword, :a, fun)
      {1, []}
      iex> Keyword.pop_lazy(keyword, :b, fun)
      {13, [a: 1]}

  """
  @spec pop_lazy(t, key, (() -> value)) :: {value, t}
  def pop_lazy(keywords, key, fun)
      when is_list(keywords) and is_function(fun, 0) do
    case fetch(keywords, key) do
      {:ok, value} ->
        {value, delete(keywords, key)}
      :error ->
        {fun.(), keywords}
    end
  end

  @doc """
  Returns and removes the first value associated with `key` in the keyword list.

  Duplicated keys are not removed.

  ## Examples

      iex> Keyword.pop_first([a: 1], :a)
      {1, []}
      iex> Keyword.pop_first([a: 1], :b)
      {nil, [a: 1]}
      iex> Keyword.pop_first([a: 1], :b, 3)
      {3, [a: 1]}
      iex> Keyword.pop_first([a: 1, a: 2], :a)
      {1, [a: 2]}

  """
  @spec pop_first(t, key, value) :: {value, t}
  def pop_first(keywords, key, default \\ nil) when is_list(keywords) do
    case :lists.keytake(key, 1, keywords) do
      {:value, {^key, value}, rest} -> {value, rest}
      false -> {default, keywords}
    end
  end

  @doc """
  Returns the keyword list itself.

  ## Examples

      iex> Keyword.to_list([a: 1])
      [a: 1]

  """
  @spec to_list(t) :: t
  def to_list(keyword) when is_list(keyword) do
    keyword
  end

  @doc false
  # TODO: Remove on 2.0
  def size(keyword) do
    IO.warn "Keyword.size/1 is deprecated, please use Kernel.length/1"
    length(keyword)
  end
end
